0.01x^2+0.01x+7=0.01x+8

Solution for 0.01x^2+0.01x+7=0.01x+8 equation:

0.01x^2+0.01x+7=0.01x+8

We move all terms to the left:

0.01x^2+0.01x+7-(0.01x+8)=0

We get rid of parentheses

0.01x^2+0.01x-0.01x-8+7=0

We add all the numbers together, and all the variables

0.01x^2-1=0

a = 0.01; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·0.01·(-1)
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.04}}{2*0.01}=\frac{0-\sqrt{0.04}}{0.02}
=-\frac{\sqrt{}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.04}}{2*0.01}=\frac{0+\sqrt{0.04}}{0.02}
=\frac{\sqrt{}}{0.02}
$